05 ନିରନ୍ତରତା ଏବଂ ଭିନ୍ନତା
ବ୍ୟାୟାମ 02
Question:
Differentiate the function with respect to xcosx^3.sin^2(x^5)
Answer:
Answer:
Step 1: Differentiate the function with respect to x:
f’(x) = cosx^3.sin^2(x^5)
Step 2: Differentiate the function with respect to cosx^3:
f’(cosx^3) = sin^2(x^5)
Step 3: Differentiate the function with respect to sin^2(x^5):
f’(sin^2(x^5)) = 2sin(x^5)cos(x^5)
Question:
Differentiate the function with respect to x 2√cot(x^2)
Answer:
Step 1: Take the derivative of the inside function, cot(x^2), with respect to x.
Step 2: Apply the chain rule to the outside function, 2√, with respect to x.
Step 3: Multiply the derivatives of the inside and outside functions together.
Answer: -4x√cot(x^2) csc^2(x^2)
Question:
Differentiate the function with respect to x sec(tan(√x))
Answer:
Step 1: Rewrite the function as sec(arctan(√x))
Step 2: Use the Chain Rule and differentiate with respect to x:
d/dx sec(arctan(√x)) = sec(arctan(√x))sec2(arctan(√x))(1/2)*(1/x^(1/2))
Step 3: Simplify the expression:
d/dx sec(arctan(√x)) = (1/2)*sec(arctan(√x))*sec2(arctan(√x))*x^(-1/2)
Question:
Differentiate the function with respect to x sin(ax+b)
Answer:
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Differentiate the function: d/dx[sin(ax+b)]
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Use the chain rule: d/dx[sin(ax+b)] = d/du[sin(u)] * d/dx[ax+b]
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d/du[sin(u)] = cos(u)
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d/dx[ax+b] = a
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Substitute: d/dx[sin(ax+b)] = a*cos(ax+b)
Question:
Differentiate the function with respect to x cos(√x)
Answer:
Given, f(x) = cos(√x)
Step 1: Take the derivative of f(x) with respect to x.
f’(x) = -sin(√x) × (1/2√x)
Step 2: Substitute the value of f’(x) in the given equation.
Differentiate the function with respect to x cos(√x) = -sin(√x) × (1/2√x)
Question:
Differentiate the function with respect to x sin(ax+b)/cos(cx+d)
Answer:
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(a*cos(ax+b)*cos(cx+d)-sin(ax+b)csin(cx+d))/(cos(cx+d))^2
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(a*cos(ax+b)*cos(cx+d)-sin(ax+b)csin(cx+d))/(cos(cx+d))^2 * (dcos(cx+d)-csin(cx+d))
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(a*cos(ax+b)*dcos(cx+d)-sin(ax+b)ccos(cx+d)-asin(ax+b)csin(cx+d)+csin(ax+b)*sin(cx+d))/(cos(cx+d))^3
Question:
Differentiate the function with respect to x sin(x^2+5)
Answer:
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Differentiate the inside of the function with respect to x: (2x)
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Multiply the result by the outside of the function: (2x)sin(x^2+5)
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Simplify: 2xcos(x^2+5)
Question:
Differentiate the function with respect to x cos(sinx)
Answer:
Step 1: Take the derivative of cos(sinx) with respect to x.
Step 2: Use the Chain Rule:
d/dx[cos(sinx)] = -sin(sinx) * d/dx[sinx]
Step 3: Take the derivative of sinx with respect to x.
d/dx[sinx] = cosx
JEE ଅଧ୍ୟୟନ ସାମଗ୍ରୀ (ଗଣିତ)
01 ସମ୍ପର୍କ ଏବଂ କାର୍ଯ୍ୟ
02 ଓଲଟା ଟ୍ରାଇଗୋନେଟ୍ରିକ୍ କାର୍ଯ୍ୟଗୁଡ଼ିକ
03 ମ୍ୟାଟ୍ରିକ୍ସ
04 ନିର୍ଣ୍ଣୟକାରୀ
05 ନିରନ୍ତରତା ଏବଂ ଭିନ୍ନତା
- ବ୍ୟାୟାମ 01
- ବ୍ୟାୟାମ 02
- ବ୍ୟାୟାମ 03
- ବ୍ୟାୟାମ 04
- ବ୍ୟାୟାମ 05
- ବ୍ୟାୟାମ 06
- ବ୍ୟାୟାମ 07
- ବ୍ୟାୟାମ 08
- ବିବିଧ ବ୍ୟାୟାମ
06 ଡେରିଭେଟିକ୍ସର ପ୍ରୟୋଗ
07 ଇଣ୍ଟିଗ୍ରାଲ୍
08 ଇଣ୍ଟିଗ୍ରାଲ୍ସର ପ୍ରୟୋଗ
09 ଭେକ୍ଟର୍
10 ତିନୋଟି ଡାଇମେନ୍ସନାଲ୍ ଜ୍ୟାମିତି
11 ରେଖା ପ୍ରୋଗ୍ରାମିଂ
12 ସମ୍ଭାବନା