15 सांख्यिकी
अभ्यास 02
Question:
Find the mean and variance for the data 6,7,10,12,13,4,8,12
Answer:
Mean:
Step 1: Add all of the data points together: 6 + 7 + 10 + 12 + 13 + 4 + 8 + 12 = 72
Step 2: Divide the sum by the number of data points: 72 ÷ 8 = 9
Therefore, the mean is 9.
Variance:
Step 1: Calculate the mean: 6 + 7 + 10 + 12 + 13 + 4 + 8 + 12 = 72; 72 ÷ 8 = 9
Step 2: Subtract the mean from each data point and square the result: (6 - 9)² = 9, (7 - 9)² = 4, (10 - 9)² = 1, (12 - 9)² = 9, (13 - 9)² = 16, (4 - 9)² = 25, (8 - 9)² = 1, (12 - 9)² = 9
Step 3: Add all of the squared results together: 9 + 4 + 1 + 9 + 16 + 25 + 1 + 9 = 73
Step 4: Divide the sum of the squared results by the number of data points: 73 ÷ 8 = 9.125
Therefore, the variance is 9.125.
Question:
Find the mean and variance for the first n natural numbers
Answer:
Step 1: Calculate the mean of the first n natural numbers. Mean = (n+1)/2
Step 2: Calculate the variance of the first n natural numbers. Variance = (n^2 - 1)/12
Question:
Find the mean and variance for the data xi 6 10 14 18 24 28 30 fi 2 4 7 12 8 4 3
Answer:
Step 1: Find the sum of all the values of xi: xi 6 10 14 18 24 28 30 fi 2 4 7 12 8 4 3
Sum of xi = 6 + 10 + 14 + 18 + 24 + 28 + 30 = 120
Step 2: Find the sum of all the values of fi: fi 2 4 7 12 8 4 3
Sum of fi = 2 + 4 + 7 + 12 + 8 + 4 + 3 = 40
Step 3: Find the mean: Mean = (Sum of xi) / (Sum of fi) Mean = 120 / 40 Mean = 3
Step 4: Find the variance: Variance = [(xi - Mean)2 x fi] / (Sum of fi) Variance = [(6 - 3)2 x 2 + (10 - 3)2 x 4 + (14 - 3)2 x 7 + (18 - 3)2 x 12 + (24 - 3)2 x 8 + (28 - 3)2 x 4 + (30 - 3)2 x 3] / 40 Variance = [9 x 2 + 49 x 4 + 91 x 7 + 153 x 12 + 576 x 8 + 784 x 4 + 841 x 3] / 40 Variance = 11,068 / 40 Variance = 276.7
Question:
Find the mean and variance for the data xi 92 93 97 98 102 104 109 fi 3 2 3 2 6 3 3
Answer:
Step 1: Find the mean. Mean = (92 x 3 + 93 x 2 + 97 x 3 + 98 x 2 + 102 x 6 + 104 x 3 + 109 x 3)/(3 + 2 + 3 + 2 + 6 + 3 + 3) Mean = (2748 + 1862 + 2910 + 1956 + 6120 + 3120 + 3267)/20 Mean = 20,823/20 Mean = 1041.15
Step 2: Find the variance. Variance = [(92 - 1041.15)2 x 3 + (93 - 1041.15)2 x 2 + (97 - 1041.15)2 x 3 + (98 - 1041.15)2 x 2 + (102 - 1041.15)2 x 6 + (104 - 1041.15)2 x 3 + (109 - 1041.15)2 x 3]/20 Variance = [(−49.15)2 x 3 + (−48.15)2 x 2 + (−44.15)2 x 3 + (−43.15)2 x 2 + (−39.15)2 x 6 + (−37.15)2 x 3 + (−32.15)2 x 3]/20 Variance = [2411.0225 + 2304.0225 + 1957.0225 + 1858.0225 + 1529.0225 + 1382.0225 + 1026.0225]/20 Variance = 10,599.3/20 Variance = 529.965
Hence, the mean and variance for the given data are 1041.15 and 529.965 respectively.
Question:
The diameters of circles (in mm) drawn in a design are given below : Diameters No. of circles 33−36 15 37−40 17 41−44 21 45−48 22 49−52 25
Answer:
Step 1: Calculate the total number of circles in the design.
Total number of circles = 15 + 17 + 21 + 22 + 25 = 100
Step 2: Calculate the sum of all the diameters of the circles.
Sum of all the diameters = (33 + 36) x 15 + (37 + 40) x 17 + (41 + 44) x 21 + (45 + 48) x 22 + (49 + 52) x 25 = 10,455
Step 3: Calculate the average diameter of the circles.
Average diameter = 10,455 / 100 = 104.55 mm
Question:
Find the mean and standard deviation using short-cut method Xi 60 61 62 63 64 65 66 67 68 fi 2 1 12 29 25 12 10 4 5
Answer:
Step 1: Find the mean. Mean = (60 x 2) + (61 x 1) + (62 x 12) + (63 x 29) + (64 x 25) + (65 x 12) + (66 x 10) + (67 x 4) + (68 x 5) / (2 + 1 + 12 + 29 + 25 + 12 + 10 + 4 + 5)
Mean = 6,506 / 87
Mean = 74.76
Step 2: Find the standard deviation. Standard Deviation = √[(60-74.76)2 x 2 + (61-74.76)2 x 1 + (62-74.76)2 x 12 + (63-74.76)2 x 29 + (64-74.76)2 x 25 + (65-74.76)2 x 12 + (66-74.76)2 x 10 + (67-74.76)2 x 4 + (68-74.76)2 x 5] / (2 + 1 + 12 + 29 + 25 + 12 + 10 + 4 + 5)
Standard Deviation = √[(-14.76)2 x 2 + (-13.76)2 x 1 + (-12.76)2 x 12 + (-11.76)2 x 29 + (-10.76)2 x 25 + (-9.76)2 x 12 + (-8.76)2 x 10 + (-7.76)2 x 4 + (-6.76)2 x 5] / 87
Standard Deviation = 3.853
Question:
Find the mean and variance for the first 10 multiples of 3
Answer:
Step 1: List the first 10 multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30
Step 2: Calculate the mean: Mean = (3 + 6 + 9 + 12 + 15 + 18 + 21 + 24 + 27 + 30) / 10 Mean = 135 / 10 Mean = 13.5
Step 3: Calculate the variance: Variance = [(3 - 13.5)2 + (6 - 13.5)2 + (9 - 13.5)2 + (12 - 13.5)2 + (15 - 13.5)2 + (18 - 13.5)2 + (21 - 13.5)2 + (24 - 13.5)2 + (27 - 13.5)2 + (30 - 13.5)2] / 10 Variance = [(-10.5)2 + (-7.5)2 + (-4.5)2 + (-1.5)2 + (1.5)2 + (4.5)2 + (7.5)2 + (10.5)2 + (13.5)2 + (16.5)2] / 10 Variance = [110.25 + 56.25 + 20.25 + 2.25 + 2.25 + 20.25 + 56.25 + 110.25 + 182.25 + 272.25] / 10 Variance = 835 / 10 Variance = 83.5
Question:
Find the mean and variance for the following frequency distribution Classes 0-30 30-60 60-90 90-120 120-150 150-180 180-210 Frequencies 2 3 5 10 3 5 2
Answer:
Mean:
Add the midpoints of each class: 0 + 30 + 60 + 90 + 120 + 150 + 180 = 630
Divide by the total number of classes: 630 / 7 = 90
Mean = 90
Variance:
Step 1: Find the deviation of each class from the mean: 0-30: 30 - 90 = -60 30-60: 60 - 90 = -30 60-90: 90 - 90 = 0 90-120: 120 - 90 = 30 120-150: 150 - 90 = 60 150-180: 180 - 90 = 90 180-210: 210 - 90 = 120
Step 2: Square the deviations: (-60)2 = 3600 (-30)2 = 900 02 = 0 302 = 900 602 = 3600 902 = 8100 1202 = 14400
Step 3: Multiply the squared deviations by the frequencies: 3600 x 2 = 7200 900 x 3 = 2700 0 x 5 = 0 900 x 10 = 9000 3600 x 3 = 10800 8100 x 5 = 40500 14400 x 2 = 28800
Step 4: Add the products from Step 3: 7200 + 2700 + 0 + 9000 + 10800 + 40500 + 28800 = 104400
Step 5: Divide the sum from Step 4 by the total number of frequencies: 104400 / 25 = 4176
Variance = 4176
Question:
Find the mean and variance for the following frequency distrubution Classes 0-10 10-20 20-30 30-40 40-50 Frequencies 5 8 15 16 6
Answer:
Mean =
(05 + 108 + 2015 + 3016 + 40*6)/(5+8+15+16+6)
Mean = 20
Variance =
[(0-20)^25 + (10-20)^28 + (20-20)^215 + (30-20)^216 + (40-20)^2*6]/(5+8+15+16+6)
Variance = 200
Question:
Find the mean variance and standard deviation using short-cut method Height in cms No. of children 70-75 3 75-80 4 80-85 7 85-90 7 90-95 15 95-100 9 100-105 6 105-110 6 110-115 3
Answer:
Step 1: Calculate the Mid-point of each class:
Height (cms) No. of children Mid-point (x) 70-75 3 72.5 75-80 4 77.5 80-85 7 82.5 85-90 7 87.5 90-95 15 92.5 95-100 9 97.5 100-105 6 102.5 105-110 6 107.5 110-115 3 112.5
Step 2: Calculate the Frequency (f):
Height (cms) No. of children Mid-point (x) Frequency (f) 70-75 3 72.5 3 75-80 4 77.5 4 80-85 7 82.5 7 85-90 7 87.5 7 90-95 15 92.5 15 95-100 9 97.5 9 100-105 6 102.5 6 105-110 6 107.5 6 110-115 3 112.5 3
Step 3: Calculate the Sum of Mid-point (x) and Frequency (f):
Sum of x = 72.5 + 77.5 + 82.5 + 87.5 + 92.5 + 97.5 + 102.5 + 107.5 + 112.5 = 825
Sum of f = 3 + 4 + 7 + 7 + 15 + 9 + 6 + 6 + 3 = 60
Step 4: Calculate the Mean (x̅):
Mean (x̅) = 825/60 = 13.75
Step 5: Calculate the Deviation (d):
Deviation (d) = x - x̅
Step 6: Calculate the Variance (σ2):
Variance (σ2) = d2 x f
Step 7: Calculate the Standard Deviation (σ):
Standard Deviation (σ) = √σ2
जेईई अध्ययन सामग्री (गणित)
01 सेट
02 संबंध एवं फलन
03 त्रिकोणमितीय फलन
04 गणितीय आगमन का सिद्धांत
05 सम्मिश्र संख्याएँ और द्विघात समीकरण
06 रैखिक असमानताएँ
07 क्रमचय और संचय
08 द्विपद प्रमेय
09 अनुक्रम और श्रृंखला
10 सीधी रेखाओं का अभ्यास
10 सीधी रेखाएँ विविध
11 शांकव खंड
12 त्रिविमीय ज्यामिति का परिचय
13 सीमाएं और डेरिवेटिव
14 गणितीय तर्क
15 सांख्यिकी
16 प्रायिकता