02 ଓଲଟା ଟ୍ରାଇଗୋନେଟ୍ରିକ୍ କାର୍ଯ୍ୟଗୁଡ଼ିକ

ବ୍ୟାୟାମ 01

Question:

Find the principal value of cot−1(√3).

Answer:

Answer: Step 1: Recall that cot−1(x) is the inverse of cot(x).

Step 2: Recall that cot(x) = cos(x)/sin(x).

Step 3: Substitute √3 for x in the equation cot(x) = cos(x)/sin(x).

Step 4: Solve for cos(x)/sin(x) = √3.

Step 5: Recall that cos(x) = sin(90° - x).

Step 6: Substitute 90° - x for cos(x) in the equation sin(90° - x)/sin(x) = √3.

Step 7: Solve for sin(90° - x)/sin(x) = √3.

Step 8: Recall that sin(90° - x) = cos(x).

Step 9: Substitute cos(x) for sin(90° - x) in the equation cos(x)/sin(x) = √3.

Step 10: Solve for cos(x)/sin(x) = √3.

Step 11: Recall that cot-1(x) is the inverse of cot(x).

Step 12: Substitute the value obtained in Step 10 for x in the equation cot-1(x).

Step 13: The principal value of cot−1(√3) is 60°.

Question:

Find the principal value of sec−1(2​/√3).

Answer:

Step 1: Find the inverse of secant.

The inverse of secant is cosecant, which is written as csc or cosec.

Step 2: Substitute the given value in the cosecant equation.

csc^−1(2/√3)

Step 3: Solve for the principal value.

The principal value of csc−1(2/√3) is 60°.

Question:

Find the principal value of cos−1(√3/2)

Answer:

Answer: Step 1: Convert √3/2 into a decimal by dividing 3 by 2.

Answer: 1.5

Step 2: Calculate the inverse cosine of 1.5.

Answer: The principal value of cos−1(√3/2) is 60°.

Question:

Find the principal value of tan−1(−√3).

Answer:

Step 1: Recall that tan−1(x) is the inverse of the tangent function, which is equal to the angle whose tangent is equal to x.

Step 2: Since tan−1(−√3) is the angle whose tangent is equal to -√3, we can use a trigonometric identity to solve for the angle.

Step 3: The identity we will use is tan(α) = -√3, where α is the angle we are trying to find.

Step 4: Solving for α, we get α = tan−1(-√3).

Step 5: The principal value of tan−1(−√3) is -60°.

Question:

Find the principal value of cos−1(−1​/√2)

Answer:

Answer:

  1. cos^-1(x) is the inverse cosine function, which is also known as the arccosine function.
  2. To find the principal value of cos−1(-1/√2), we need to calculate the arccosine of -1/√2.
  3. Using a calculator, we can find that the arccosine of -1/√2 is equal to 3π/4.
  4. Therefore, the principal value of cos−1(-1/√2) is 3π/4.

Question:

Find the principal value of cosec−1(2).

Answer:

Step 1: Recall that cosec−1(x) is the inverse of cosec(x).

Step 2: Recall that cosec(x) = 1/sin(x).

Step 3: Set 1/sin(x) = 2.

Step 4: Solve for x by taking the inverse sine of both sides.

Step 5: The principal value of cosec−1(2) is π/3 radians.

Question:

Find the value of tan−1(1)+cos−1(−1​/2)+sin−1(−1​/2).

Answer:

Step 1: tan−1(1) = π/4

Step 2: cos−1(−1​/2) = 3π/4

Step 3: sin−1(−1​/2) = -π/2

Step 4: Add the three values together: π/4 + 3π/4 + (-π/2) = π/2

Therefore, the value of tan−1(1)+cos−1(−1​/2)+sin−1(−1​/2) is π/2.

Question:

Find the principal value of cos−1(−1​/2).

Answer:

Step 1: Recall that the principal value of cos−1(x) is the angle θ in the interval [0, 2π] such that cos(θ) = x.

Step 2: We are given that x = −1/2.

Step 3: Solve the equation cos(θ) = −1/2 to find θ.

Step 4: Using a calculator or a table of values, we find that θ = 2.094395102393195 radians.

Step 5: Therefore, the principal value of cos−1(−1/2) is 2.094395102393195 radians.

Question:

Find the principal value of sin−1(−1​/2)

Answer:

Step 1: Recall that sin−1(x) is the inverse of the sine function, which is also known as the arcsin function.

Step 2: Use the arcsin function to find the principal value of -1/2.

Step 3: The principal value of sin−1(-1/2) is -π/6.

Question:

Find the principal value of cosec−1(−√2)

Answer:

Answer: Step 1: Recall that cosec−1(x) = arcsin(1/x)

Step 2: Substitute -√2 for x in the equation: cosec−1(-√2) = arcsin(1/(-√2))

Step 3: Simplify the expression: cosec−1(-√2) = arcsin(-1/√2)

Step 4: Use a calculator to find the principal value of arcsin(-1/√2): cosec−1(-√2) = -π/4

Question:

Find the value of cos−1(1​/2)+2sin−1(1​/2)

Answer:

Given, cos−1(1/2) + 2sin−1(1/2)

Step 1: Calculate the value of cos^−1(1/2)

cos−1(1/2) = 60°

Step 2: Calculate the value of sin−1(1/2)

sin−1(1/2) = 30°

Step 3: Substitute the values in the given equation.

60° + 2(30°) = 120°

Hence, the value of cos−1(1/2) + 2sin−1(1/2) = 120°.

Question:

Find the value of tan−1 √3 −sec−1(−2) is equal to A π B −π​/3 C 3π​ D 2π/3

Answer:

Answer: B -π/3

Question:

Find the principal value of tan−1(−1).

Answer:

Step 1: Recall that the principal value of tan−1(x) is the angle measured in the counterclockwise direction from the positive x-axis to the ray from the origin that intersects the point (x,y).

Step 2: In this case, x = -1, so the principal value of tan−1(-1) is the angle measured in the counterclockwise direction from the positive x-axis to the ray from the origin that intersects the point (-1,y).

Step 3: Since y = -1, the principal value of tan−1(-1) is the angle measured in the counterclockwise direction from the positive x-axis to the ray from the origin that intersects the point (-1,-1).

Step 4: Therefore, the principal value of tan−1(-1) is π radians or 180°.

JEE ଅଧ୍ୟୟନ ସାମଗ୍ରୀ (ଗଣିତ)

01 ସମ୍ପର୍କ ଏବଂ କାର୍ଯ୍ୟ

02 ଓଲଟା ଟ୍ରାଇଗୋନେଟ୍ରିକ୍ କାର୍ଯ୍ୟଗୁଡ଼ିକ

03 ମ୍ୟାଟ୍ରିକ୍ସ

04 ନିର୍ଣ୍ଣୟକାରୀ

05 ନିରନ୍ତରତା ଏବଂ ଭିନ୍ନତା

06 ଡେରିଭେଟିକ୍ସର ପ୍ରୟୋଗ

07 ଇଣ୍ଟିଗ୍ରାଲ୍

08 ଇଣ୍ଟିଗ୍ରାଲ୍ସର ପ୍ରୟୋଗ

09 ଭେକ୍ଟର୍

10 ତିନୋଟି ଡାଇମେନ୍ସନାଲ୍ ଜ୍ୟାମିତି

11 ରେଖା ପ୍ରୋଗ୍ରାମିଂ

12 ସମ୍ଭାବନା